Bag 1: 2R, 1B
Bag 2: 1R, 1B, 2Y
Draw 1 from each bag
a) P(same color)
We have 2/3 chance of drawing R from bag 1 and a 1/4 chance of drawing R from bag 2
P(both R) = (2/3)(1/4) = 1/6
We have a 1/3 chance of drawing B from bag 1 and 1/4 chance of B from bag 2
P(both B) = (1/3)(1/4) = 1/12
P(same color) =1/6 + 1/12 = 3/12 = 1/4
Answer: a) 1/4
b) P(exactly one R)
Same story except we look at the complement in bag 2
We have 2/3 chance of drawing R from bag 1 and a 1/4 chance of drawing R from bag 2, so a 3/4 chance of NOT drawing R.
P(1st red, second not red) = (2/3)(3/4) = 1/2
We have 1/3 chance of drawing B from bag 1, so 1/3 chance of drawing NOT red from bag 1. We have a 1/4 chance of drawing R from bag 2, so
P(1st blue, second not blue) = (1/3)(1/4) = 1/12
P = 1/2 + 1/12 = 6/12 + 1/12 = 7/12
Answer: 7/12
Answer:0.21 the large box
Step-by-step explanation: find unit rate for each box.
$1.25/5=$.25 - small
$2.07/9=$.23 - medium
$3.15/15=$.21 - large
Answer: 2√10 - √30
explanation:
ok so they’re asking for the difference between the lengths of the sides of each cube. they have different SA’s (surface areas). all you gotta do is plug in the SA in the given equation to find the length of the side and THEN you subtract the answers and thats how you find the difference between the sides.
given:
s = √(SA/6)
SA1 = 240 m^2
SA2 = 180 m^2
S1 = √(240/6) = 2√10 or 6.32
S2 = √(180/6) = √30 or 5.47
s1 -s2 = 2√10 - √30
Answer:False
Step-by-step explanation:
Value 14 so it must be 55 or something
