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3 years ago

NEED ANSWER RIGHT NOW PLS Which graph represents the solution set of the inequality Negative 9 greater-than x?

Mathematics

2 answers:

Rasek [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Agata [3.3K]3 years ago

3 0

Answer:

i think C

Step-by-step explanation:

tell me if i am wrong and hope you have a good day

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There are 84 students in the glee club there are 12 more boys than girls what is the ratio of the number of girls to the number

Masja [62]

Let us denote the number of boys in the glee club with X and the number of girls with Y.There are 84 students in the glee club, which means that the following equation can be written:X+Y=84We also now that there are 12 more boys than girls, so:X=Y+12We can rewrite the first equation like:(Y+12)+Y=842Y+12=842Y=62Y=62/2=31X=31+12=43So, the ratio of the number of girls to the number of boys is: Y/X=31/43
Read more on Brainly.com - brainly.com/question/4711779#readmore

5 0

3 years ago

Solve for a,b 2^a × 2^b=144 value of a+3b+2 is... please solve it...urgent...

Nadya [2.5K]

Answer:

its a simple for me

Step-by-step explanation:

2+144 i

4 0

3 years ago

True or False, when graphing an inequality that has no solutions, you shade the entire number line.

Over [174]

Answer:

True or False

2. When graphing inequalities, a dashed line is used for < or > signs.

True or False

3. If you were to graph x > 6, the circle would be closed and to the left.

True or False

4. On a number line, if you were to graph an equation with a less than sign or a great than sign, < or > respectively, you would use an open circle

True or False

6 0

3 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

Make X the subject of the formula will mark brainliest!!

irga5000 [103]

Answer:

$y = \frac{x + 2}{x - 4} \\ xy - 4y = x + 2 \\ xy - x = 4y + 2 \\ x(y - 1) = 4y + 2 \\ x = \frac{4y + 2}{y - 1} \\ \boxed{x = \frac{2(2y + 1)}{y - 1} }$

hope this helps.

3 0

2 years ago