a population of 430 animals decreases at an annual rate of 21% find the multiplier for the rate of exponential decay

2 answers:

8 0

If the population of the animals decreases by about 21% of its current population, it means that the population next year is only 1 - 0.21 or 0.79 of its current population. Thus, the multiplier for the rate of the exponential decay is 0.79.

scoray [572]3 years ago

4 0

Answer:

0.79

Step-by-step explanation:

We have been given that a population of 430 animals decreases at an annual rate of 21%. We are asked to find the multiplier for the rate of exponential decay.

We know that an exponential decay function is in form $y=a\cdot (1-r)^x$ , where,

a = Initial value,

r = Decay rate in decimal form.

Let us convert 21% in decimal form as:

$21\%=\frac{21}{100}=0.21$

Upon substituting our given values, we will get:

$y=430\cdot (1-0.21)^x$

$y=430\cdot (0.79)^x$

Therefore, the multiplier for the rate of exponential decay is 0.79.

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