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2 years ago

Add 2 then add 4! I dont get it at all plz help!

1 answer:

3 0

The question could be asking one of two things. If it is asking for you to create an equation that represents that, the equation would be:

x+2+4

We can find this by breaking apart the question. Since we are not given a variable, we can assume x. Then, you can reference "add 2" for where I got the "+2." Finally, you can see the "add 4," which is where I got the "+4."

If the question is referring to simple addition, you can simply add these numbers together. If you are really struggling, you should use a calculator and input these values. To improve your basic addition skills, you can practice with the popular elementary "finger-counting method" where you hold up the value of one of the numbers on one hand, and the other value on the other hand, and then count how many fingers are up.

If you need any further explanation, please let me know and I will be happy to assist you! :)

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Please help ASAP 40 pts

natali 33 [55]

Answer:

x=2

Step-by-step explanation:

We know AC = BC since this is an isosceles triangle

6 = 2x+2

Subtract 2 from each side

6-2 =2x+2-2

4 =2x

Divide each side by 2

4/2 =2x/2

2=x

4 0

3 years ago

Read 2 more answers

10+x/2

Pavlova-9 [17]

Answer:

The answer will be 12 please mark me as brainliest

6 0

2 years ago

HELPPPPPPPPP

Evgesh-ka [11]

Answer:

D-last pic

Step-by-step explanation:

Check the rate of change in the f(x) column.

The first 3 have linear change (arithmetic sequence) and the last one has different pattern.

Correct option is D

7 0

3 years ago

Find the quotient of these Complex Numbers. (5-i) / (3+2i)

JulsSmile [24]

Let the given complex number

z = x + ix = $\dfrac{5-i}{3+2i}$

We have to find the standard form of complex number.

Solution:

∴ x + iy = $\dfrac{5-i}{3+2i}$

Rationalising numerator part of complex number, we get

x + iy = $\dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}$

⇒ x + iy = $\dfrac{(5-i)(3-2i)}{3^2-(2i)^2}$

Using the algebraic identity:

(a + b)(a - b) = $a^{2}$ - $b^{2}$

⇒ x + iy = $\dfrac{15-10i-3i+2i^2}{9-4i^2}$

⇒ x + iy = $\dfrac{15-13i+2(-1)}{9-4(-1)}$ [ ∵ $i^{2} =-1$ ]

⇒ x + iy = $\dfrac{15-2-13i}{9+4}$

⇒ x + iy = $\dfrac{13-13i}{13}$

⇒ x + iy = $\dfrac{13(1-i)}{13}$

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0

3 years ago

Does 14 and 10 have the same factor

iVinArrow [24]

Answer:

Yes

Step-by-step explanation:greatest common factor (GCF) of 10 and 14 is 2. We will now calculate the prime factors of 10 and 14, then find the greatest common factor (greatest common divisor (gcd)) of the numbers by matching the biggest common factor of 10 and 14.

4 0

2 years ago