On your graph, draw a horizontal line at y=5. Basically a line over (-3,5) to (3,5) or whatever the greatest x's are. Since it is greater than or equal to, it is a solid line. Greater than, you shade above the line
Answer:
friday
Step-by-step explanation:
Because in the numerator and denominator of the fraction 1a/3a, you're able to simplify that and get 1/3. There is actually no solution to the problem you're asking. You're unable to find out what (a) equals.
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
Answer:
141, meaning that there will be two real solutions
Step-by-step explanation:
The discriminant of a quadratic is
, which in this case is:

Since the discriminant is positive and not zero, there will be two real solutions to this equation. This is because when the discriminant is negative, and you take the square root of it, you get a negative number. If you take the square root of 0, you get 0, which means that there will only be one solution to the equation.
Hope this helps!