Answer: -120
Step-by-step explanation:
this would be the answer because if you take a positive and add it to a negative you get zero if their the additive inverse of the number.
The difference quotient of the expression will be 4.
<h3>How to find the quotient?</h3>
f(x) = 5 + 5x + 4x²
f(3) = 5 + 5(3) + 4(3)³
= 56
Now [f(x) - f(3)]/(x - 3) will be:
= (4x² + 5x + 5 - 56)/(x - 3)
= (4x² + 5x - 51)/(x - 3)
= (4x² + 17x - 12x - 5)/(x - 3)
= (4x + 17)(x - 3)/(x - 3)
= 4x + 17
The difference quotient will be:
g(x + h) = 4(x + h) + 17
= [g(x + h) - g(x)]/h
= (4x + 4h + 17 - 4x - 17)/h
= 4h/h
= 4
Learn more about quotient on:
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Answer:
-30, 2, -9
Explanation:
Coefficients are the constant quantity placed before and multiplying the variable in an algebraic expression.
(Including whether its a positive or negative)
The answer is
<span>x+1</span>, <span>x+2</span>, <span>x+3</span>, <span>x+4</span> and <span>x+5</span>.
The sum of these six integers is 393 so we can write:
<span>x+x+1+x+2+x+3+x+4+x+5=393</span>
<span>6x+1+2+3+4+5=393</span>
<span>6x+15=393</span>
<span>6x+15−15=393−15</span>
<span>6x+0=378</span>
<span><span><span>6x</span>6</span>=<span>3786</span></span>
<span>x=63</span>
Because the first integer is 63 then the third would be <span>x+2</span> or <span>63+2=<span>65</span></span>
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<span><span>Hope its helps :)</span></span>