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stellarik [79]
2 years ago
10

Karen rode her bike at a constant speed of 10 miles per hour. Her distance d is proportional to the number of hours she rode, t.

Select 2 equations that represent this situation?
Mathematics
1 answer:
NeTakaya2 years ago
5 0

Answer:

s = d/t and d = s × t

Step-by-step explanation:

s = d/t

d = s × t

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Help me out please, thanks
aev [14]

Hello!

f(x) = x² + 12x <=>

<=> a = 1, b = 12 <=>

<=> x = -12/2×1 <=>

<=> x = -6 <=>

<=> f(-6) = -36 <=>

<=> (-6; -36)

Good luck! :)

8 0
2 years ago
How do you do this problem?
astra-53 [7]
By substitution is how to solve

2x-3y=21
y=3-x

2x-3(3-x)=21 
2x-9+3x=21
5x=30
x= 6

now substitute our x value into y=3-x
so we get 

y=3-6 = -3

so x=6 and y=-3  hope this helps!!!!! Thank you!
5 0
3 years ago
Read 2 more answers
If one meter is approximately 3.28ft how many meters are in 20 ft
shusha [124]

Answer:

I think the answer is 6.096 Meters.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Tobin rows 2 miles per hour faster than her opponent. If it takes Tobin 30 minutes to finish a race, and it takes her opponent 4
Sunny_sXe [5.5K]
If we represent Tobin's speed as x, we can write her opponent's speed as 
x-2 (since Tobin is 2 more than them). In addition, since it's in miles per hour, and 45 minutes is 3/4 of an hour, we can say that 3/4ths of her speed in miles per hour is how long the race is, so (3/4)(x-2)=distance of race. In addition, since it only took Tobin 30 minutes, and 30 minutes is half an hour, x/2 (half of her miles per hour) is the length of the race, so (3/4)(x-2)=(1/2)x. Expanding it, we get 3x/4-6/4=x/2. Subtracting x/2 (or 2x/4) from both sides, we get x/4-6/4=0 and by adding 6/4 to both sides we get x/4=6/4. Multiplying 4 to both sides, we get that x=6=Tobin's speed in miles per hour
6 0
3 years ago
Please help! Big grade! Extra points!! Help asap!
Sonbull [250]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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