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3 years ago

Question 18 (4 points)

Mathematics

1 answer:

devlian [24]3 years ago

8 0

The answer would be (-5x-3)(-5x+3)

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Can someone help me with this math problem please and thank you. :-)

jok3333 [9.3K]

Triangle ABE is isosceles / Given

AB congruent to AE / Def isosceles

angle ABE congruent to angle AEB / Property of isosceles triangles

angle ABD congruent to angle AEC / Subst different name for same angles

BD congruent to EC / Given

triange ABD congruent to triange AEC / Side Angle Side

5 0

2 years ago

Finding the discriminant

mario62 [17]

I believe the answer you are looking for is 16

7 0

3 years ago

A triangle has side lengths of ( 5.9 k + 9.3 m ) (5.9k+9.3m) centimeters, ( 3.6 k − 3.9 n ) (3.6k−3.9n) centimeters, and ( 3.5 n

Lilit [14]

Answer:

(9.5k + 12.7m -0.4n) cm

Step-by-step explanation:

(5.9k+9.3m) + (3.6k−3.9n) + (3.5n+3.4m) = 9.5k + 12.7m -0.4n

8 0

2 years ago

Write two ratios that are equivalent to 5/7

lisov135 [29]

Ratios equivalent to 5:7

10:14

20:28

30:42

hope this helps :D

8 0

2 years ago

Read 2 more answers

Christian has a cookie recipe that yields four dozen cookies and calls for 2 1/4 cups white sugar and 3/4 cup brown sugar.cif ch

Paha777 [63]

The ingredients given are for 4 dozen cookies; however, Christian only want to make one dozen, meaning he requires only 1/4 the ingredients.

1/4 of 2 1/4 cups of while sugar is found the following way.

First, we write 2 1/4 as an improper fraction

$2\frac{1}{4}=2+\frac{1}{4}=\frac{9}{4}$

1/4 of this is

$\frac{9}{4}\times\frac{1}{4}=\frac{9}{16}$

Hence, Christian requires 9/16 cups of white sugar.

Similarly, the 1/4 of 3/4 cups of brown sugar is

$\frac{1}{4}\times\frac{3}{4}=\frac{3}{16}$

Hence, Chrisitan requires 3/16 cups of brown sugar.

Therefore, the total cups of sugar required is the sum of

$\frac{3}{16}+\frac{9}{16}=\frac{12}{16}=\frac{3}{4}$

3/4 cups of sugar.

7 0

1 year ago