Answer:
66.48% of full-term babies are between 19 and 21 inches long at birth
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean length of 20.5 inches and a standard deviation of 0.90 inches.
This means that 
What percentage of full-term babies are between 19 and 21 inches long at birth?
The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then
X = 21



has a p-value of 0.7123
X = 19



has a p-value of 0.0475
0.7123 - 0.0475 = 0.6648
0.6648*100% = 66.48%
66.48% of full-term babies are between 19 and 21 inches long at birth
If you would like to order the following values in descending order, you can do this using the following steps:
- 3/4 = - 0.75
1/8 = 0.125
- 0.735
7/8 = 0.875
1/80 = 0.0125
0.056
The result is: 7/8, 1/8, 0.056, 1/80, - 0.735, -0.75.
The triangle drawn in the question shows a small single line drawn across two sides of the triangle.
This means that those two sides are equal in length.
Hence, the triangle is an isosceles triangle.
In isosceles triangles, the angles opposite to the equal sides are also equal.
Hence, we know that the two angles other than x is 56°.
The sum of the interior angles of a triangle is 180°
x + 56 + 56 = 180
x = 180 - 56 - 56
x = 180 - 112
x = 68°
Hence, the answer is A.
Answer:
or 
Step-by-step explanation:




For sin θ = 0.5, the reference angle is θ = 30 deg.

or 