The point (-3,4) is reflected across the x-axis. What is the coordinates of its new location?

Mathematics

1 answer:

Tasya [4]3 years ago

4 0

Semd a pic of a graph bc I dont have paper

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Given that f(x) = 2x2 − 96, find x.

NISA [10]

F(x)=2x(2)−96

Step 1: Add -4x to both sides.

xf+ −4x = 4x−96+ −4x

xf −4x= −96

Step 2: Factor out variable x.

x(f−4)= −96

Step 3: Divide both sides by f-4.

x(f−4)/ f−4 = −96/ f−4

x= −96/f−4

Answer:

x= −96/ f−4

3 0

4 years ago

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What’s the answer to this?!!

Basile [38]

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3 years ago

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$