Find the slope and y-intercept from the following graph of a linear equation.

a recipe for 1 handmade pizza calls for 2 1/2 cups all purpose flour. Showing your work below, how many cups of all purpose flou

KatRina [158]

You need to use the cross product method to find your answer :

1 pizza = 2 ½ cups
3 pizzas = × cups

((2 ½) • 3) ÷ 1 = × cups

7 ½ ÷ 1 = × cups

7 ½ = × cups

⇨ So your answer is: You would need to use 7 ½ cups of flour to make 3 handmade pizzas!

There you go. I really hope this helped, if there’s anything just let me know! ☻

3 0

3 years ago

Latasha earned 18 points on her quiz. If 24 points is equivalent to a score of 100% what two proportions could she use to calcul

Ugo [173]

Given:
18 points on her quiz
24 points is equivalent to 100%

18 is to 24 or 18/24
x is to 100% or x/100%

18/24 = x/100%

18 * 100% = 24x
1800% = 24x
1800%/24 = x
75% = x

18/24 = 75%/100%
18 * 100% = 24 * 75%
1800% = 1800%

6 0

3 years ago

I will give brainliest if you wanttt!

NikAS [45]

Answer:

8 + 1.5x + 0.75y = pizza_cost

Step-by-step explanation:

It is given that every 10-inch cheese pizza costs ($8), meaning that this will be the constant.

Let (x) represent the number of inches added to the pizza. Since each extra additional inch costs ($1.5) thus one adds (1.5x) to the equation.

Let (y) represent the number of toppings. Every extra topping costs ($0.75) therefore one has to add (0.75y) to the equation.

Putting all of the elements together one gets the equation,

8 + 1.5x + 0.75y

4 0

3 years ago

A donation center had filled up 44 small bins with canned food with each bin containing 24 cans. They plan to send the cans out

Valentin [98]

Each food bank would receive 264 cans.

44 Bins with 24 cans. 44•24= 1,056

n= (44•24) / 4
n= 1,056 / 4
n= 264 cans per food bank

8 0

3 years ago

According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

3 years ago