Question

(10g^2 +3g-10) + (2g^2+g+7)

Answer 1

Hey!

Let's write the problem.
$\left(10g^2+3g-10\right)+\left(2g^2+g+7\right)$
Remove the parenthesis.
$=10g^2+3g-10+2g^2+g+7$
Add like terms...
$3g+g=4g$
$10g^2+2g^2=12g^2$
We would be left with something like this,
$=12g^2+4g+7-10$
Subtract the numbers.
$=12g^2+4g-3$
That would be our final answer!

Thanks!
-TetraFish