Long division: (x³ + 2) ÷ (x + 1)
<u> </u><u>x² – x + 1 </u>
x³ + 0x² + 0x + 2 | x + 1
<u>– x³ – x²</u> ⋮ ⋮
– x² + 0x ⋮
<u>+ x² + x</u><span> ⋮</span>
+ x + 2
<span> </span> <u>– x – 1</u>
+ 1
Quotient: Q(x) = x² – x – 1;
Remainder: R(x) = + 1.
I hope this helps. =)
Answer:
1) It is given that line AB is tangent to the circle at A.
∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact)
Thus, the measure of ∠CAB is 90º.
The correct answer is <span>A) P'(3, −4), Q'(−3, 4), R'(6, −3)</span>
Rx = 0 indicates a reflection over the y-axis.
The rule for such a transformation is:
(x, y) --> (-x, y)
which means that the x-coordinate changes sign and the y-coordinate stays the same.
Therefore:
P<span>(-3, -4) --> P'(3, -4)
Q(3, 4) --> Q'(-3, 4)
R(-6, -3)</span> --> R'(6, -3)
These points are those in option A).
3x + 4y = 16
-4x - 3y = -19
4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1
Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4
Answer:
x = 4
y = 1
