Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer: G
Step-by-step explanation:
Answer:
2bc
Step-by-step explanation:
can't tell how i got it but 2bc is the answer
Answer:
(x, y ) → (x + 6, y - 10 )
Step-by-step explanation:
6 units right is + 6 in the x- direction
10 units down is - 10 in the y- direction
the translation rule is
(x, y ) → (x + 6, y - 10 )
Answer:
<h2>h = 4 cm</h2><h2 />
Step-by-step explanation:
V = π r² h
where r = 3 cm
V = 36π cm³
solve for h
plugin values into the formula:
36π = π 3² h
h = <u> 36π </u>
π 3²
h = 4 cm