Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
The Area of the Rectangle = l × w
<> 10 × 8 = 80 ft²
The Area of the Semicircle = ½
The Area of a circle = ½ (πr²)
<> π = 3.14
<> r = ½ of 8 = 4 ft
<> ½(3.14 × 4) = 6.28 ft²
The Area of the figure = Area of rectangle + Area of semicircle:-
<> 80 ft² + 6.28 ft² = <u>86.28</u><u> </u><u>ft</u><u>²</u>
Therefore, The area of the figure is <u>86.28</u><u> </u><u>ft</u><u>²</u>.
The total area is 17.15cm cubed
I think it is 16... since 2•2=4 and if it does not give you your b(base) or l(length) it will automatically become the other number