A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
If the question was -20.48 divided by -4 then the answer is 5.12
Answer:
D. 
inches.
Step-by-step explanation:
We have been given that the circle with center O has a minor arc BSA with a length of 
inches. The central angle is 40°.
To find the circumference of circle we will use formula:
, where 
= measure of 360 degrees in radians and 
= circumference of circle.
Let us convert measure of central angle into radians.
Upon substituting our given value in the formula we will get,
Cross multiplying we will get,
Hence, the radius of our circle is 27/4 inches.
Since the circumference of circle is . Upon substituting we will get,
Therefore, circumference of our given circle will be inches and option D is the correct choice.
