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Rainbow [258]
3 years ago
13

Mrs. Grundy has two children. Given that Mrs. Grundy has at least one child born on a Monday, what is the probability that both

her children were born on Mondays? Assume that each child was equally likely to be born on any day of the week, and that the two birthdays are independent (Mrs. Grundy doesn't have twins!).
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

1/7

Step-by-step explanation:

If one child was born on a Monday, then we don't have to consider that when solving the question, as it asks if both children were born on a Monday.

Thus, we only need to find the probability that the second child is born on a Monday. Since there are 7 days in a week and equally likely that the child is born on any day, then the probability of the child being born on a Monday would be 1/7.

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The ADMHS football team is trying to raise money to buy new equipment so the players are selling "Jaguar Cards" for $20 each. If
alekssr [168]

Answer:

The inequality to represent the situation is 20x\geq 3000 and the team must sell at least 15 "Jaguar Cards".

Step-by-step explanation:

Given: The ADMHS football team is trying to raise money to buy new equipment so the players are selling "Jaguar Cards" for \$20 each.

If the football team needs to raise at least \$3,000 for equipment.

To find: The inequality to represent the situation and the least number of "Jaguar Cards" the team must sell.

Solution:

Let the ADMHS football team sold x "Jaguar Cards" for \$20 each.

Now, the football team needs to raise at least \$3,000 for equipment.

So, the inequality to represent the situation is 20x\geq 3000.

Now, on solving we get,

20x\geq 3000

\implies x\geq \frac{300}{20}

\implies x\geq 15

Hence, the inequality to represent the situation is 20x\geq 3000 and the team must sell at least 15 "Jaguar Cards".

4 0
3 years ago
Can someone help me please
vovikov84 [41]
X=7




Explanation:

A triangle equals 180°, and they gave us one length already, and it says the one arm of the triangle is equal to the other so we know that the third angle is going to be the same as the second angle.


180=90+(6x+3)+(6x+3)
Combine like terms
180=96+12x
Subtract 96 from both sides
84=12x
Divide 12 by both sides
7=x


Now check it,

90+(6*7+3)+(6*7+3)
90+(45)+(45) =180
8 0
3 years ago
Cynthia's uncle told her to save 20% of her earnings
WARRIOR [948]
Find 100/20 x 30
=150
4 0
3 years ago
A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8
Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that \mu = 61, \sigma = 8

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 61}{8}

X - 61 = -0.675*8

X = 55.6

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

Z = \frac{X - \mu}{\sigma}

2.96 = \frac{X - 61}{8}

X - 61 = 2.96*8

X = 84.68

The minimum score for an A is 84.68.

8 0
3 years ago
it is equally probable that the pointer on a spinner will land on any one of the eight regions. if the spinner lands on a boarde
Tamiku [17]

Answer:

1/3

Step-by-step explanation:

3 0
3 years ago
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