All categories

3 years ago

4 x plus 8 y equals 40, when y equals 0.8?

Mathematics

1 answer:

kondor19780726 [428]3 years ago

3 0

Answer:

When x = 8.4 and y = .8 then 4x + 8y = 40

Step-by-step explanation:

4x + 8y = 40

y = .8

Let's solve for x by substituting .8 for y (since y is given)

4x + 8(.8) = 40

4x + 6.4 = 40 Subtract 6.4 from both sides.

4x + 6.4 - 6.4 = 40 - 6.4

4x = 33.6 Divide each side by 4

4x/4 = 33.6/4 4 cancels on the left because 4/4 = 1

x = 33.6/4

x = 8.4

So when x = 8.4 and y = .8 then 4x + 8y = 40

You might be interested in

Has anybody done this problem before on Carnegie learning Mathia I’ve been stuck on this problem and I need to turn in this assi

Vinil7 [7]

Answer:

Conclusion: ◇WAU ≅ ◇JAU

Reason: ASA theorem

Step-by-step explanation:

6 0

3 years ago

How to tell if a 15 year old boy likes me quiz for 13 year olds?

EleoNora [17]

Http://www.allthetests.com/quiz30/quiz/1379266484/Does-He-Like-you-Back-10-13-year-olds-ONLY

3 0

3 years ago

The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g

andrezito [222]

I'll denote the identity function by $\mathrm{Id}$ . Then for any functions $f$ with inverse $f^{-1}$ ,

$\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}$

One important fact is that composition is associative, meaning for functions $f,g,h$ , we have

$(f\circ g)\circ h=f\circ(g\circ h)$

So given

$h=f\circ g$

we can compose the functions on either side with $g^{-1}$ :

$h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})$

then apply the rules listed above:

$h\circ g^{-1}=f\circ\mathrm{Id}=f$

3 0

3 years ago

Which Relation Is A Function ?

adoni [48]

The first one because for every output there is only 1 input

8 0

2 years ago

Simplify the the problem 2x^2-4x-390=0

Sergio039 [100]

Answer:

The answer is <em>-195</em>

7 0

3 years ago