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stealth61 [152]
3 years ago
12

4x+y=10 solve the missing value

Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer:

2

Step-by-step explanation:

4x + y = 10 \\ 4(2) + 2 = 10

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Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
viktelen [127]
For this case we have the following equation:
 d = 0.5 + 5t
 We will describe the equation step by step.
 0.5: Initial distance Jillian walked
 5: speed with which Jillian begins to jog
 t: independent variable that indicates the number of hours
 y: dependent variable that indicates the distance traveled in miles
 Answer:
 
The variable variable is time and the dependent variable is distance.
3 0
3 years ago
Read 2 more answers
The measure of the vertex angle of an isoceles triangle is one- fourth that of a base angle
horsena [70]

Answer:

Base angle = 72

Vertex angle = 18

Step-by-step explanation:

Measure of the base angle = x. But there are two of them. (Definition of isosceles).  Keep that in mind.

The vertex angle is 1/4 of one of the base angles. That means that the vertex is 1/4 x

All three angles = 180 degrees.

So we have x + x + x/4 = 180 degrees.

change 1/4x to 0.25x x since 1/4 = 0.25

Equation

x + x + 0.25 = 180

2.5x  = 180

Solution

2.5x = 180                      Divide by 2.5 on both sides

2.5x/2.5 = 180/2.5

x = 72

Answer

That means that each base angle = 72 degrees

The Vertex Angle = 72/4 = 18

8 0
4 years ago
There are the two photos to solve it and jus write A B or C please
Sidana [21]
The answer would be B
8 0
3 years ago
What is the exact volume of a cylinder that has a height of 1.8 ft and a radius of 6.1 ft?
lozanna [386]
Cylinder area=height times area of base (area of base=area of circle)

height =1.8
radius=6.1
area of circle=pi times r^2


area of circle=pi times 6.1^2=37.21π
times height

1.8 times 37.21π=66.978π

volume=66.978π ft^3
3 0
3 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
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