Graph y-3=1^2(x+2) on a sheet of paper please
1 answer:
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Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
Answer:
s = 11
Step-by-step explanation:
Given
= 22 ← substitute r = 242
= 22 ( multiply both sides by s )
242 = 22s ( divide both sides by 22 )
11 = s