Question

Need help with powers of powers!!!

Answer 1

$\bf 81h^8k^6\quad \begin{cases} 81=9^{1\cdot 2}\\ h^8=h^{2\cdot 4}\\ k^6=k^{3\cdot 2} \end{cases}\implies 9^{1\cdot \stackrel{\downarrow }{2}}h^{\stackrel{\downarrow }{2}\cdot 4}k^{3\cdot \stackrel{\downarrow }{2}}\implies (9^1h^4k^3)^{\stackrel{\downarrow }{2}} \\\\\\ (9h^4k^3)^2$