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3 years ago

Which linear equation has a slope of 3 and a y-intercept of -2?

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

8 0

Answer:

y=3x-2

Step-by-step explanation:

3 is the coefficient of x (slope)

-2 comes after (y-int)

never [62]3 years ago

8 0

Answer:

y = 3x – 2

Step-by-step explanation:

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Kim creates a model of a building. The scale of her model building is 1 foot to 8 inch. Some of the measurements are shown in th

Shalnov [3]

Answer:

Left

50 feet

Right

16 inches

10 inches

Step-by-step explanation:

Here, we want to make a conversion and fill in the empty spaces

The scale is 1 foot is 1/8 inch

To convert from foot to inch, we multiply by 1/8

To convert from inch to foot, we multiply by 8

Thus, we have ;

Let’s fill in the left spaces first;

6.25 * 8 = 50 feet

Right spaces, top to bottom;

128 * 1/8 = 16 inches

80 * 1/8 = 10 inches

7 0

2 years ago

Find polynomial whose zeros are 3 and -4

horrorfan [7]

Answer:

Simplest polynomial: x²+x-12

Step-by-step explanation:

zeroes of polynomial= 3,-4

Therefore,

f(3) =0

f(-4)=0.

By factor Theorem

(x-3) and (x+4) are factors

so simplest polynomial is

(x-3)(x+4)

= x² - 3x + 4x -12

= x² + x -12

Hope it helps

6 0

2 years ago

Pls help just please will mark BRAINLIEST

Darina [25.2K]

Answer:

44.2545

Step-by-step explanation:

you can find the third angle by taking 180-(90+55)=a

a=35

use law of sines

Sin(angle)/(opposite side of angle)=Sin(another angle)/(opposite side of another angle)

so, sin(a)/A=sin(b)/B

sin(35)/33=sin(55)/x

x=sin(55)/(sin(35)/33)

x=44.2545

Hope this helps :)

3 0

2 years ago

Peter works as a delivery person for a bike shipping company. The graph shows a linear model for his

evablogger [386]

Answer/Step-by-step explanation:

a. Using a point on the graph, (6, 12), and the slope of the line, we can first generate an equation in the point-slope form, given as $y - b = m(x - a)$ , where,

m = slope, and (a, b) is a point on the line.

Using two points, (6, 12) and (3, 21), let's find slope, m.

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{21 - 12}{3 - 6} = \frac{9}{-3} = -3$

Using a point (6, 12) and slope, m = -3, generate an equation in the point-slope form by substituting a = 6, b = 12, and m = -3 in $y - b = m(x - a)$ .

✅Equation in point-slope form would be:

$y - 12 = -3(x - 6)$

Rewrite this to make it be in the slope-intercept form, $y = mx + b$ .

$y - 12 = -3(x - 6)$

$y - 12 = -3x + 18$

Add 12 to both sides

$y = -3x + 18 + 12$

$y = -3x + 30$

✅The equation in slope-intercept form is $y = -3x + 30$

b. ✍️Based on the linear model, $y = -3x + 30$ , the 30 represents b = y-intercept.

✅Therefore, it took Peter 30 mins long initially to deliver his package.

✍️Based on the linear model, $y = -3x + 30$ , "-3" represents the slope.

✅Therefore, Peter's delivery time decreased 3 mins per day.

6 0

2 years ago

If u(x)=-2x²+3 and v(x)=1/x, what is the range of (u ° v)(x)?

Ludmilka [50]

$u(x)=-2x^2+3\\\\v(x)=\dfrac{1}{x}\\\\(u\ \circ\ v)(x)=-2\left(\dfrac{1}{x}\right)^2+3=-2\left(\dfrac{1}{x^2}\right)+3=-\dfrac{1}{x^2}+3\\\\\text{The range of}\ y=\dfrac{1}{x^2}\ \text{is all positive real numbers.}\\\\\text{The range of}\ y=-\dfrac{1}{x^2}\ \text{is all negative real numbers.}\\\\\text{The range of }\ (u\ \circ\ v)(x)=-\dfrac{1}{x^2}+3\ is\ (-\infty,\ 3)$

6 0

3 years ago

Read 2 more answers