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Zigmanuir [339]
3 years ago
14

Max's car holds 18 gallons of gasoline. Driving on the highway, the car uses approximately 2 gallons per hour. Let h represent t

he number of hours Max has been driving on the highway. Write an expression that shows how many gallons of gasoline Max has left after driving h hours.
Mathematics
1 answer:
Mice21 [21]3 years ago
3 0
Y= 18 gallons-2(h)
y is what you're trying to find out and since there are 18 gallons in the tank after every hour you would have 2 less gallons. So, you can multiply how many hours he's been driving by the 2 gallons and subtract it from 18


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I need help! Will mark Brainliest for full answer!!!
Softa [21]

<u><em>Answer:</em></u>

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

<u><em>Explanation:</em></u>

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

<u>Mathematically, an inverse variation relation is represented as follows:</u>

y = \frac{k}{x}

where x and y are the two variables and k is the constant of variation

<u><em>Now, let's check the givens:</em></u>

<u>Part a:</u>

We are given that y = 3 and k = 33

<u>Substitute in the original relation and solve for x as follows:</u>

y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11

<u>Part b:</u>

We are given that y = 11 and x = 5.2

<u>Substitute in the original relation and solve for k as follows:</u>

y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2

<u>Part c:</u>

We are given that x=7.8 and k=72

<u>Substitute in the original relation and solve for y as follows:</u>

y=\frac{k}{x}=\frac{72}{7.8}=9.2 to the nearest tenth

Hope this helps :)

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