Which statement is true of a reversible reaction at equilibrium?'
2 answers:
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Answer:
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
Explanation:
The two types of acetaldehyde transition are as follows:
n→π* and π→π*
From the attached diagram we have to:
ΔEn→π* < ΔEπ→π*
ΔEα(1/λ)
Thus:
λn→π* > λπ→π*
In n→π* spin forbidden, the intensity is low. Thus, the molar extinction E for n→π* is very low.
The same way, for π→π* spin allowed the intensity is high. Thus, the molar extinction coefficient E for π→π* is high too.
The bands are due to:
λmax = 289 nm n→π* transition (E = 12)
λmax = 182 nm π→π* transition (E=10000)
Answer:
0.322 moles
Explanation:
Given Mass, m = 100 g
The molar mass of Ca₃(PO₄)₂
Ca₃(PO₄)₂ = (3 x 40.08) + (2 x 30.97) + (8 x 16.00)
M = 310.18 g/mol
Let there are n number of moles,
n = given mass/ molar mass
So, there are 0.322 moles.