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gtnhenbr [62]
3 years ago
12

Rank the following solutes in order of increasing entropy when 0.0100 moles of each dissolve in 1.00 liter of water.

Chemistry
1 answer:
sergeinik [125]3 years ago
8 0

Answer:

CH3OH, NaBr, CaCl2, Cr(NO3)3

Based on disorderliness, the ionization strength gives the entropy.

CH3OH - Does not ionize, it's a solvent

NaBr- Ionizes intwo two ions

CaCl2- Ionizes to three ions 1Ca and 2 Cl ions

Cr(NO3)3- Ionizes to four ions

Explanation:

Here is the complete question:.

Rank the following solutes in order of increasing entropy when 0.0100 moles of each dissolve in 1.00 liter of water.

CaCl2, CH3OH, Cr(NO3)3, NaBr

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OverLord2011 [107]

Answer:

Explanation:

13 ) symbol of enthalpy change = Δ H .

14 ) enthalpy change is nothing but heat absorbed or evolved .

During fusion enthalpy change

Δ H .= m Lf , m is mass and Ls is latent heat of fusion

During evaporation, enthalpy change

Δ H .= m Lv , m is mass and Lv is latent heat of evaporation

during temperature rise , enthalpy  change

Δ H = m c Δ T

In case of gas , enthalpy change can be calculated by the following relation

Δ H = Δ E + W , Δ E is change in internal energy , W is work done by gas.

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A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t
andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

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from the principle of:

heat lost = heat gained

heat gained by water is given by:

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Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

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Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

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Shtirlitz [24]

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How much Oxygen would be required to react with 101 g of Methane?
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Answer:

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Explanation:

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