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Scrat [10]
2 years ago
14

What element is in group 17 and period 2 of the periodic table?

Chemistry
1 answer:
Natali [406]2 years ago
3 0

Answer:

Group 17 elements:

Flourine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (As).

Period 2 elements:

Lithium (Li), Beryllium (Be), Boron (B), carbon (C), Nitrogen (N), Oxygen (O), flourine (F), And Neon.

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Chamber 1 and Chamber 2 have equal volumes of 1.0L and are assumed to be rigid containers. The chambers are connected by a valve
vitfil [10]
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas  than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)

=> p1 = 2 p2

Which is easy to demonstrate using ideal gas equation:

p1 = nRT/V = 2.0 mol * RT / 1 liter

p2 = nRT/V = 1.0 mol * RT / 1 liter

=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2

2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.

So, the pressure in both chambers (which form one same vessel) is:

p = nRT/V = 3.0 mol * RT / 2liter

which compared to the initial pressure in chamber 1, p1, is:

p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1

So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.

You can also see how the pressure in chamber 2 changes:

p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
5 0
3 years ago
Plesse help asap!!!​
Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

8 0
2 years ago
Which set of chemical name and chemical formula for the same compound is correct??
Kruka [31]
The correct answer to your question is: <span>C) tin (IV) bromide, SnBr₄</span>
5 0
3 years ago
A sample of a mineral solid weighing 28.5 g was added to a graduated cylinder filled with to a level of 20.3 mL. As a result, th
bonufazy [111]

Answer:

2.8 g/mL is the density of the mineral.

Explanation:

The mass, m=28.5\ g

Volume of the object = Volume of water level rose - Initial volume of water = 30.5 mL - 20.3 mL = 10.2 mL

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

\rho=\frac{28.5\ g}{10.2 mL}=2.8\ g/mL

<u>2.8 g/mL is the density of the mineral.</u>

8 0
3 years ago
below left is a cylinder containing water. an ball with a mass of 21g and a volume of 15 cm3 is lowered into the water. sketch t
anyanavicka [17]

You didn’t show the cylinder containing water, so I created one that you can use as a model (see image).

The water level was originally at 37 mL.

Then you added the ball, and it displaced its volume of water.

The new volume reading is 52 mL, so

Volume of ball = volume of displaced water = 52 mL – 37 mL = 15 mL.

8 0
3 years ago
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