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Scrat [10]
3 years ago
14

What element is in group 17 and period 2 of the periodic table?

Chemistry
1 answer:
Natali [406]3 years ago
3 0

Answer:

Group 17 elements:

Flourine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (As).

Period 2 elements:

Lithium (Li), Beryllium (Be), Boron (B), carbon (C), Nitrogen (N), Oxygen (O), flourine (F), And Neon.

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Need help fast please 15 points!!!
In-s [12.5K]

Answer:

C. disposition and condensation ​

Explanation:

8 0
2 years ago
You work for a cutlery manufacturer who wants to electrolytically precipitate 0.500 g of silver onto each piece of a batch of 25
ICE Princess25 [194]

Answer:

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

Explanation:

Mass of silver to be precipitated on ecah spoon = 0.500 g

Number of silver spoons = 250

Total mass of silver = 250 × 0.500 g = 125 g

Moles (n)=Molarity(M)\times Volume (L)

Moles of AgCN = n  = \frac{125 g}{134 g/mol}=0.9328 mol

Volume of AgCN solution =V

Molarity of the AgCN = 2.50 M

V=\frac{0.9328 mol}{2.50 M}=0.3731 L=373.1 mL

(1 L = 1000 mL)

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

6 0
3 years ago
When an aqueous solution of silver nitrate is
Andre45 [30]

Answer:

K^{+} and NO_{3}^{-}

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

Ag^{+}(aq) + NO_{3} ^{-}(aq) + K^{+}(aq) + Cl^{-}(aq)  ==> AgCl(s) +

K^{+} and NO_{3} ^{-} do not change, so they are the spectator ions and are removed

The ionic equation is:

Ag^{+}(aq) + Cl^{-}(aq) ==> AgCl(s)

8 0
2 years ago
Use the information below, to write a word equation, then change it into a balanced symbol equation.
Kamila [148]

Answer:

Mg    +  2HCl  -> MgCl2   + H2

Explanation:

7 0
3 years ago
When you are converting grams to moles , are you multiplying or dividing ?
Effectus [21]
When you are converting grams to moles, the operation that you will be doing is dividing by the molar mass to obtain the amount of moles of the given sample.
4 0
3 years ago
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