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3 years ago

How does an atom-88 become a strontium ion with a +2 charge?

Chemistry

1 answer:

Fantom [35]3 years ago

6 0

Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom. Your answer is C.

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Boron has an atomic mass of 10.811. What does this mean?

icang [17]

Answer:

Knowing that boron has an atomic mass of 10,811 means that all boron isotopes on average weigh 10,811 u.

Explanation:

The atomic mass of an atom is the mass of the atom measured in u (unified atomic mass unit), although we can also express it as Da (Dalton's unit)

Atomic mass refers to the average mass that all isotopes of that element have.

When we speak of isotopes we are referring to the element itself but with a different number of neutrons, which makes it modify its mass number.

6 0

3 years ago

What is the attraction between molecules within a substance called? adhesion capillary action cohesion polarity.

cestrela7 [59]

Answer:

cohesion

Explanation:

just got it right

5 0

2 years ago

Read 2 more answers

A chemist prepares a solution of sodium carbonate by measuring out of sodium carbonate into a volumetric flask and filling the f

Vadim26 [7]

Answer:

The correct answer will be " $9.45\times 10^{-5} \ mol/L$ ".

Explanation:

We have:

Moles of solute (Na₂Co₃) = $18.9 \mu \ mol$

= $18.9\times 10^{-6}$

$1 \mu \ mol$ = $10^{-6} \ mol$

Now,

The volume of the solution will be:

⇒ $0.200 \ L$

∴ ${1 \ mL=0.001 \ L}$

The formula to find the concentration will be:

⇒ $Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}$

On substituting the given values, we get

⇒ $=\frac{18.9\times 10^{-6}}{0.200}$

⇒ $=9.45\times 10^{-5} \ mol/L$

8 0

3 years ago

Natasha_Volkova [10]

to be honestl id ldm

4 0

3 years ago

How many liters are in a 0.115 M solution containing 1.55 moles of dissolved KBr?

Anika [276]

13.48 is your answer.

M=moles/liters we have M=.115 and moles=1.55

Input those values into the equation
.115=1.55/L

Solve for L
1.55/.115=13.48

5 0

3 years ago