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horrorfan [7]
3 years ago
7

How does an atom-88 become a strontium ion with a +2 charge?

Chemistry
1 answer:
Fantom [35]3 years ago
6 0

Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom. Your answer is C.

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The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
5 0
3 years ago
The Heliocentric model is when the sun, planets, and stars are orbiting a stationary Earth.
Anarel [89]
False

A heliocentric is when the model is
representing the sun as the center
A geocentric says the earth is at the center of the universe
3 0
2 years ago
Which begins as chemical energy and can be transformed into electricity?
Umnica [9.8K]
Sunlight i think thats the answer
8 0
3 years ago
Which property of water explains why seawater contains over 20 different elements? select one:
Gnesinka [82]
I believe the awnser is a. universal solvent.
8 0
3 years ago
Read 2 more answers
Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h
andrew11 [14]

Answer : The change in entropy is 6.05\times 10^3J/K

Explanation :

Formula used :

\Delta S=\frac{m\times L_v}{T}

where,

\Delta S = change in entropy = ?

m = mass of water = 1.00 kg

L_v = heat of vaporization of water = 2256\times 10^3J/kg

T = temperature = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}

\Delta S=6048.25J/K=6.05\times 10^3J/K

Therefore, the change in entropy is 6.05\times 10^3J/K

5 0
3 years ago
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