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Lorico [155]
4 years ago
9

Maria wants to determine which type of disinfectant kills the most bacteria.

Chemistry
2 answers:
murzikaleks [220]4 years ago
6 0

Answer:

well she can test both of the soap by putting one on and plate and another on the other plate and which ever is cleaner is your answer

morpeh [17]4 years ago
4 0

Answer:

Put the same amount and species of bacteria on ten identical plates, and add a different disinfectant to each plate.

Explanation:

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What happens if the solvent solute attraction is greater than the salute solute attraction when to substances are mixed
dolphi86 [110]

Answer:

What happens if the solvent-solute attraction is greater than the solute-solute attraction when two substances are mixed? The solute particles are pulled apart and dispersed throughout the particles of the solvent, which holds the particles of the solute in solution.

Explanation:

5 0
2 years ago
After Michelle went on vacation for two weeks, she came home to find her potted plants had turned brown and died. The soil was v
attashe74 [19]

<em>Answer:</em>

<em>A</em>

<em>Explanation:</em>

<em>The explanation lies in the answer. Plants need all components to make their own food.</em>

5 0
3 years ago
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Yanka [14]

It avoids confusion through scientists. If you think, they could be practicing or studying in varying countries and something uniform for science avoids all confusion!

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3 years ago
In the PhET simulation window, click the Macro menu in the top left corner of the screen. This view gives a view of the beaker a
babymother [125]

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5 0
3 years ago
A 100.0g sample of lead is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water at
AURORKA [14]

Answer : The specific heat capacity of lead is, 0.119J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of lead = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of lead = 100.0 g

m_2 = mass of water = 150.0 g

T_f = final temperature = 26.4^oC

T_1 = initial temperature of lead = 100.0^oC

T_2 = initial temperature of water = 25^oC

Now put all the given values in the above formula, we get

100.0g\times c_1\times (26.4-100.0)^oC=-150.0g\times 4.184J/g^oC\times (26.4-25)^oC

c_1=0.119J/g^oC

Therefore, the specific heat capacity of lead is, 0.119J/g^oC

5 0
3 years ago
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