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I am Lyosha [343]
3 years ago
9

Can anyone teach me how to do acid and base? (chemistry)

Chemistry
2 answers:
NARA [144]3 years ago
3 0
Acids have a PH level of 6 or lower
Bases have a PH of 8 or higher
PH 7 is neutral
elena55 [62]3 years ago
3 0
For the topic of conjugate acids and bases you know that the if you have an acid (sometimes labeled as HA), its conjugate base is HA minus one H⁺ ion (sometimes called a proton).  The conjugate base of HCl is Cl₋, the conjugate base of H₂SO₄ is HSO₄⁻, the conjugate base of CH₃COOH is CH₃COO⁻, and so on.  To find the conjugate acid of a base, you have to reverse that process.  The conjugate acid of HCO₃⁻ is H₂CO₃, the conjugate acid of NH₃ is NH₄⁺, the conjugate acid of PO₄³⁻ is HPO₄²⁻, and so on.  

examples:
HCl+H₂O⇒H₃O⁺+Cl⁻
acid=HCl, base=H₂O, conjugate base=Cl⁻, and conjugate acid=H₃O⁺

NH₃+H₂O⇒NH₄⁺+OH⁻
acid=H₂O, base=NH₃, conjugate base=OH⁻, and conjugate acid=NH₄⁺

I hope this helps.  Let me know if anything is unclear or you want me to explain anything further.
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Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F

The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).

Where H = Heat, s  =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.

On plugging the values we get:

H = 135.0 g × 4.184 J/g.⁰C×(29.444 - 10.222) ⁰C

Or, H = 10857.354 J or 10.857 kJ.

Thus 10857.354 J or 10.857 kJ heat will be needed to raise the temperature.

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