The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
4x-35=9x
-4x
-35=5x
divide by 5
x= -7
30xy + 36x^2 + 30x + 25y
= 6x(5y + 6x) + 5(6x + 5y)
= (6x + 5)(6x + 5y) Answer
Answer:
5 2/5
Step-by-step explanation:
sorry, I know the answer, but don't know how to explain in words
Answer:D
Step-by-step explanation:
you plug 4 in for x
f(4)=4^2+2(4)-3
=16+8-3
=24-3
=21