<u>Answer </u><u>:</u>
This figure consists of two shapes that are a rectangle and a square . We will first find the area of rectangle then the square then add them . Let's work on this together ,
- Breadth of rectangle = 4 cm
- Length of rectangle = 4 + 5 + 3
- Length = 12 cm
- Area of rectangle = 12 × 4
- 48 cm²
Area of square ,
Total area of the figure ,
Answer:
x
∈
R
,
y
∈
[
−
2
,
∞
) mark brainliest please
Step-by-step explanation:
y is defined for all real values of x
domain is
x
∈
R
(
−
∞
,
∞
)
←
in interval notation
the quadratic in the form
y
=
x
2
+
c
has a minimum turning point at
(
0
,
c
)
y
=
x
2
−
2
is in this form with
c
=
−
2
range is
y
∈
[
−
2
,
∞
)
graph{x^2-2 [-10, 10, -5, 5]}
Answer:
S=194, L=75 L+S=269, 4L+1S=$494
Step-by-step explanation:
Answer:
Step-by-step explanation:
Divide 8 1/4 by 6 7/8 and the answer will be 1.2 times heavier.
8 1/4 is 8.25 and 6 7/8 is 6.875 in decimal point and again:
8.25 divided by 6.875 is 1.2.
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria