Answer this in 1 minute for brainiest:)

You use 33 cans of soup to serve 55 people. If you want to serve 2020 people, what should you do?

sveticcg [70]

First off, we need to find how much would a people need,by dividing the amount needed.

The equation of how much a people would need:

55÷33
=1.67 or 55/33 (it would be best to keep it in fraction to get a more precise answer)

To find out how much 2020 people need ,we would mutiply the answer above by 2020:

55/33×2020
≈3366.7
≈3367

Thus,you would have to prepare 3367 can of soup.

hope it helps!

3 0

3 years ago

Plz help ASAP the number that is cut off on 69 is 24

Minchanka [31]

Answer:

$A=256\ units^2$

Step-by-step explanation:

The given figure shows a triangular pyramid having 16 units as height. The base of pyramid is triangle.

The area of a triangular pyramid is given by :

$A=\dfrac{1}{3}bH$

Where

b is the area of base

$A=\dfrac{1}{3}\times \dfrac{1}{2}\times B\times h\times H\\\\=\dfrac{1}{6}\times 12\times 8\times 16\\\\=256\ units^2$

So, the required area is equal to $256\ units^2$ .

7 0

3 years ago

Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a

Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

$Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }$

$Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)$

$(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}$

$Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}$

$Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}$

$n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2$

$n = (16*(\frac{1.2}{(270-264)}))^2$

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0

3 years ago

Write greatest unit fractions that are repeating decimals. Then express each fraction as a decimal.

LekaFEV [45]

Our repeating decimal would be= 0.5555….
Let’s give 0.5555….. repeating decimal a variable of x:
x= 0.5555…. or 0.5(move 1 point to the right)
So ,10x = 5.5555 or 5.5

Now, Let’s do subtraction:
10x = 5.5555… or 5.5
- x = 0.5555… or 0.5
9x = 5.0 or 5.0

To get a fraction, provide a denominator the same with the numerator of variable x which is 9. Then divide the difference:
9x = 5.0
9 9 Therefore, x = 5
 9

7 0

3 years ago

So I really don't understand what I'm doing....I would be glad if you helped

SSSSS [86.1K]

We are supposed to assume FC and AD is straight line
let's find all the angles

you already see the right angle is 90 degrees, you got that right
striaght line is 180 degrees

90+46+EF=180
136+EF=180
minus 136 both sides
EF=44
now we got another straight line
you did get that A F=46 because it is oposite

notice: AB=BC because same angle designition
so now we use
180+46+2AB=360
2AB=134
divide 2
AB=67=BC
AC=134 degrees
CAE=134+46+44=224
ABD=180 since straight line

a. 90
b. 224
c.134
d. 180

8 0

3 years ago