The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π
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equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
angle of arc ACB = 360° - 35° = 325°
The length of major arc ACB = (325/360) * π * 10 = (325/36)π
The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π
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Answer:
B
Step-by-step explanation:
120+4x-12=180, 4x+108=180,4x=72, x=18
y + 11 = –2(x + 1.5)
y=mx+b
multiply the bracket by -2
(-2)(x)=-2x
(-2)(1.5)=-3
y+11=-2x-3
move +11 to the other side
sign changes from +11 to -11
y+11-11=-2x-3-11
y=-2x-14
m is also the slope
b= y-intercept
Answer:
y-intercept=-14
Given:
A circle with diameter 9 cm.
To find:
The area of the circle.
Solution:
The area of a circle is:
...(i)
Where r is the radius.
We know that, the diameter of a circle is twice than its radius.
The diameter of the given circle is 9 cm.
Substituting 
in (i), we get
Therefore, the area of the given circle is 63.6.
-5 ≤ 3m + 1 < 4
- 1 - 1 - 1
-6 ≤ 3m < 3
3 3 3
-2 ≤ m < 1
Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)
The answer is A.
