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3 years ago

Need help on all plz

Mathematics

1 answer:

olga55 [171]3 years ago

7 0

3.
a. 380 ÷ 38 = 10
b. 190 ÷ 38 = 5
c. 570 ÷ 38 = 15
d. use 10 times 38 = 380, 190 is half of 380 so half of 10 is 5, 570 is 380 + 190 so 10 + 5

4.
a. 670 ÷ 67 = 10
b. 603 ÷ 67 = 9
c. 737 ÷ 67 = 11
d. use 10 times 67 = 670, 603 is 670 - 67 so 10 - 1 = 9, 737 is 670 + 67 so 10 + 1 = 11

Challenge:
1062 - 279 = 783
$\frac{1}{3} (783)=261$
783 - 261 = 522
522 ÷ 15 = 34 remainder 12
So she put 34 books in each box

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Workers have packed 1,400 glasses in 7 boxes. If they pack 3 more boxes, how many glasses will they have packed in all?

11111nata11111 [884]

1box = 1400/7 = 200

200×3=600

1400+600=2000

8 0

4 years ago

Read 2 more answers

Mark incorrectly solved the inequality -4(5/2+3/2x) > 8. His work is shown. Which step shows an error based on the inequality

aliya0001 [1]

Answer : The incorrect step is, (A) step 1: -10 + 6x > 8

Step-by-step explanation :

The given expression is:

$-4(\frac{5}{2}+\frac{3}{2}x)>8$

Now solving this expression step by step.

First -4 distributed over parentheses.

$(-4\times \frac{5}{2})+(-4\times \frac{3}{2}x)>8$

Now solving bracket term, we get:

$-10-6x>8$

Now taking like terms together, we get:

$-6x>8+10$

$-6x>18$

$-x>3$

Now multiplying this expression by (-1), we get:

$x>-3$

Thus, the incorrect step is, (A) step 1: -10 + 6x > 8

5 0

3 years ago

The ages of adults in a certain community follow a normal distribution with mean 38 and standard deviation 6. The random variabl

nataly862011 [7]

Answer:

a = 33.32

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 38, \sigma = 6$