Question

The concession stand sells hot dogs and soda during Beck high school football games John bought six hotdogs and four Sotos and paid 6.70 just kebab for hotdogs and three sodas and paid for 4.65 what is the price of a hotdog and a soda

Answer 1

Question is not proper, Proper Question is given below;

The concession stand sells hot dogs and drinks during their high school foot ball game. John bought 6 hot dogs and 4 soda and paid $6.70. Jessica bought 4 hot dogs and 3 Soda and paid $4.65. What is the price of a hot dog and a Soda?

Answer:

Hot dog cost for $0.75 and Soda cost for $0.55.

Step-by-step explanation:

Let the Price of each Hot dog be x.

Also Let the price of each Soda be y.

Now Given:

John bought 6 hot dogs and 4 Soda and paid $6.70.

Now Total Money paid by John is equal to Sum of Number of hot dogs he bought multiplied by Cost of each hot dogs and Number of Soda he bought multiplied by cost of each soda.

Framing in equation form we get;

$6x+4y=6.70$

Dividing by 2 on both sides we get;

$\frac{6x}{2}+\frac{4y}{2}=\frac{6.70}{2}\\\\3x+2y=3.35 \ \ \ \ equation\ 1$

Also Given:

Jessica bought 4 hot dogs and 3 Soda and paid $4.65.

Now Total Money paid by John is equal to Sum of Number of hot dogs he bought multiplied by Cost of each hot dogs and Number of Soda he bought multiplied by cost of each soda.

Framing in equation form we get;

$4x+3y=4.65 \ \ \ \ equation \ 2$

Multiplying equation 1 by 3 we get;

$3(3x+2y)=3.35\times3\\9x+6y=10.05 \ \ \ \ equation \ 3$

Also Multiplying equation 2 by 3 we get;

$2(4x+3y)=4.65\times 2\\8x+6y = 9.3 \ \ \ \ equation\ 4$

Now Subtracting equation 4 from equation 3 we get;

$(9x+6y)-(8x+6y)=10.05-9.3\\9x+6y-8x-6y= 0.75\\x=\ 0.75$

Now Substituting the value of x in equation 1 we get;

$3x+2y=3.35\\\\3\times 0.75+2y = 3.35\\\\2.25+2y=3.35\\\\2y = 3.35-2.25\\\\2y = 1.1\\\\y=\frac{1.1}{2}= \ 0.55$

Hence Hot dog cost for $0.75 and Soda cost for $0.55.