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sineoko [7]
3 years ago
11

Solve the inequality. 1/3+x+2/9>5/6

Mathematics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

5⁄18 < x

Step-by-step explanation:

Start by adding like-terms [⅓ and 2⁄9] with 9 being the Least Common Denominator [LCD]. Since 2⁄9 already has a 9 in the denominator, it does not get touched, so in order to make ⅓ a denominator of 9, we simply multiply both terms by 3, to get 3⁄9. So, adding that to 2⁄9 gives you 5⁄9, also giving you <em>5⁄9</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>></em><em> </em><em>⅚.</em><em> </em>Now, we have to find the LCD again because we have two unlike fractions. Now, our Least Common Denominator is 18, so multiply both terms in ⅚ by 3 [15⁄18] and multiply both terms in 5⁄9 by 2 [10⁄18]. Now you have two like fractions to work with, and you can clearly see that your answer is <em>x</em><em> </em><em>></em><em> </em>5⁄18. Although the answer is written in reverse, it is still the same concept.

I am joyous to assist you anytime.

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Answer: B. The rate is 2, the initial value is 4, and the specific value is 6.

Step-by-step explanation:

for a linear function y = a*x + b

Rate = coefficient that is multiplicating the variable. ( a in this case)

Initial value = value taken of y, when we have x = 0 (b in this case)

Specific value = value forced on y.

In this case, we have:

y = 6 = 2*x + 4

Then:

The coefficient multiplicating x is 2, so the rate is 2.

The constant term is 4, so the initial value is 4.

The value equal to y is 6, so the specific value is 6.

The correct option is B.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Use the table below to answer this question:
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3 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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2 years ago
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