1 - (8 to the second power + 6) Which do I do first 8+6 the then exponent or Vice versa?

Mathematics

2 answers:

Svet_ta [14]3 years ago

6 0

You would need to do it vice versa

Ghella [55]3 years ago

6 0

If you follow pemdas, you would first do what is inside the parentheses, and then the exponent. In this case your exponent is inside the parentheses so you would simplify the exponent first, and then solve the rest of the problem (multiply/divide, add/subtract).

1-(8²+6)

1-(64+6)

1-70

-69

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There were 57 cars in a parking lot at 9:00 AM and 36 different cars at 8:00 PM.

Dmitry [639]

Answer:

C. 93 cars

Step-by-step explanation:

57 cars + 36 cars = 93 cars

7 0

2 years ago

Pls,pls,pls,help me I will give lots of pound 100+ points

Bond [772]

Answer:

3log(10) -2log(5) ≈ 1.60206
no; rules of logs apply to any base. ln(x) ≈ 2.302585×log(x)
no; the given "property" is nonsense

Step-by-step explanation:

The given expression expression can be simplified to ...

3log(10) -2log(5) = log(10^3) -log(5^2) = log(1000) -log(25)

= log(1000/25) = log(40) . . . . ≠ log(5)

≈ 1.60206

Or, it can be evaluated directly:

= 3(1) -2(0.69897) = 3 -1.39794

= 1.60206

The properties of logarithms apply to logarithms of any base. Natural logs and common logs are related by the change of base formula ...

ln(x) = log(x)/log(e) ≈ 2.302585·log(x)

The given "property" is nonsense. There is no simplification for the product of logs of the same base. There is no expansion for the log of a sum. The formula for the log of a power does apply:

$\log(a)\log(b)=\log(a^{\log(b)})=\log(b^{\log(a)})$