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2 years ago

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1 - (8 to the second power + 6) Which do I do first 8+6 the then exponent or Vice versa?

2 answers:

Svet_ta [14]2 years ago

6 0

You would need to do it vice versa

Ghella [55]2 years ago

6 0

If you follow pemdas, you would first do what is inside the parentheses, and then the exponent. In this case your exponent is inside the parentheses so you would simplify the exponent first, and then solve the rest of the problem (multiply/divide, add/subtract).

1-(8²+6)

1-(64+6)

1-70

-69

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2. You have $500 to invest and have several options available to you.p a. Your banker shows you the graph at right to explain wh

Vaselesa [24]

Answer:

replace x with number then multiply or divide

Step-by-step explanation:

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2 years ago

Which inequality had the graph shown below?

prisoha [69]

Answer:

y < 2x -3

Step-by-step explanation:

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3 years ago

Help please!<br> Find x<br> x=<br> 7<br> 7/2<br> /(14)

Dahasolnce [82]

Answer:

x = 7

Step-by-step explanation:

recognize that this is a right triangle with one of the internal angles = 45°. This means that the other angle not shown is 180 - 90 - 45 = 45°

This makes the triangle an isosceles triangle.

If so, x must be the same length as the other side adjacent to 90°

i.e x = 7

8 0

3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

Write two expressions to show w increased by 4. Then, draw models to prove that both expressions represent the same thing.

Vinil7 [7]

Answer:Answer:

w + 4 and 4 + w

Step-by-step explanation:

Given phrase,

w is increased by 4,

That is, w + 4

By the commutative property of addition,

The expression would be,

4 + w

For drawing a model that shows w + 4

Take two boxes in which first shows w and second shows 4 and add them,

Similarly, for showing 4 + w, take first box that shows 4 and second box that shows w then add them.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers