The Mean Value Theorem: If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that: f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a ) f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 ) f `( x ) = 10 x - 3 f ` ( c ) = 10 c - 3 2 f ` ( c ) = 16 - 2 f ` ( c ) = 7 7 = 10 c - 3 c = 1 Answer: Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).