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4 years ago

HELP ASAP!! PLZZ!

Mathematics

1 answer:

creativ13 [48]4 years ago

5 0

You must use the trigonometric function.

$\sin48^o=\dfrac{5}{h}\\\\\sin48^o\approx0.7431\\\\\dfrac{5}{h}=0.7431\\\\0.7431h=5\ \ \ \ |:0.7431\\\\h\approx6.7$
Answer: 6.7

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Graph the points (0,-2), (4,0) and (2,0). If you want to create a parallelogram, which of the following points should used for t

MariettaO [177]

( 2 , - 2 )

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3 years ago

A= 5 and c = 13 what does b =

Maru [420]

Uh it can really be anything. You should try and be more specific: see if you did the whole problem.

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3 years ago

Read 2 more answers

GUYS I NEED HELPPPPPP PLEASEEEEEEEEEEE IF YOU CAN THEN TYSM

love history [14]

Answer:

198 cubic metres

Steps:

Find the area of cross section

Area if traingle + Area of square

1/2 × 3 × 4 + 4×4

6+ 16

22

Then times with the lenght (9)

22×9

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

7 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago

HELP IM LOSIMG TIME!!!!

Kitty [74]

Answer:

20 and 40

Step-by-step explanation:

5 0

3 years ago