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Paraphin [41]
3 years ago
9

.;;;;;;;;;;;;;;;;;;;;;;;;

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

Uhm.. What is this? Just random?

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A plane travels 3,625.26 miles in 6.9 hours. What is the plane’s unit rate?
Lunna [17]

Answer:

The correct answers are:

a)\frac{3625.26 miles}{6.9hours}

b)36252.6 tenths miles÷ 69 tenths hours

c)\frac{3500miles}{7hours}= 500\frac{miles}{hour}

d)\frac{3625.26miles}{6.9hours} \frac{10}{10} =\frac{36252.6miles}{69hours}

e) 525.4 miles/h

Step-by-step explanation:

The division is solved by using the division algorithm in the attached picture.

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There are 1/3 gallon of water in a 3-gallon container. What fraction of the<br> container is filled?
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An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
2 years ago
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