What is the area of the garden?

puteri [66]

Assuming you want the expression to be simplified.

We begin with the following:

$5^{2} * 3^{-1} * \frac{5^-3}{3^{4}} * 5^{-1} * 3^{-3}$

Simplify the first part, $5^{2}$ . That is 25. Now we have this:

$25*3^{-1.5} * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3}$

Next, simplify $3^{-1}$ , which is 1/3, and get this:

$25* 1/3 * \frac{-3}{3^{4}} * 5^{-1} * 3^{-3}$

The next part is $\frac{5^-3}{3^{4}}$ . Simplify the denominator, $3^{4}$ , which is 81. Simplify the numerator, which is 1/125. Then divide 1/125 by 81, which we will keep as a fraction for simplicity's sake, but simplify it to $\frac{1}{10125}$ . Now we have:

$25* 1/3 * \frac{1}{10125} * 5^{-1} * 3^{-3}$

Now simplify $5^{-1}$ , which is 0.2, or 1/5. Now we have:

$25* 1/3 * \frac{1}{10125} * 0.2 * 3^{-3}$

Finally, simplify $3^{-3}$ . That is 1/27. We have:

$25* 1/3 * \frac{1}{10125} * 0.2 * 1/27$

Lastly, multiply them all together! Now we are done, with the product of:

$\frac{1}{6075}$

That certainly did take a while to type in all the LaTex, so I really hope that helped!

Note- if anything isn't working with the LaTex, just tell me and I'll fix it! (:

3 0

3 years ago

If 0 < b ≤ 90 and cos(11b + 2) = sin(12b − 4), what is the value of b?

Elza [17]

Answer:

b = 4

Step-by-step explanation:

The given expression is

Cos (11b + 2) = Sin (12b - 4)

Since, Sin(θ) = Cos(90 - θ)

Therefore, Cos (11b + 2) = Cos [90 - (12b - 4)]

Where 0 < b ≤ 90°

11b + 2 = 90 - (12b - 4)

11b + 2 = 94 - 12b

11b + 12b + 2 = 94 - 12b + 12b

11b + 12b + 2 - 2 = 94 - 2

23b = 92

$\frac{23b}{23}=\frac{92}{23}$

b = 4

Therefore, b = 4 will be the answer.

7 0

3 years ago

Read 2 more answers

Kindly answer this question it would be really helpfull

Svetach [21]

Answer:

The values in the table, taking into account the quadratic equation, are:

x -3 -2 -1 0 1 2 3 4
y 16 9 4 1 0 1 4 9

Step-by-step explanation:

To obtain the values of the table, you must use the quadratic equation given:

y = x^2 - 2x + 1

Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:

y = x^2 - 2x + 1
y = (-3)^2 - 2*(-3) + 1
y = 9 + 6 + 1
y = 16

When x is -1

y = x^2 - 2x + 1
y = (-1)^2 - 2*(-1) + 1
y = 1 + 2 + 1
y = 4

When x is 1

y = x^2 - 2x + 1
y = (1)^2 - 2*(1) + 1
y = 1 - 2 + 1
y = 0

When x is 3:

y = x^2 - 2x + 1
y = (3)^2 - 2*(3) + 1
y = 9 - 6 + 1
y = 4

At last, the graph must be as the attached picture I give you, but remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider.