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vitfil [10]
3 years ago
12

Explain why the exponents cannot be added in the product 12^3 and 11^3

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0
Because bases are different.

a^n · a^m = a^(n+m)
You might be interested in
Daisy's mom is 4 times as old as she.The sum of their ages 6 years ago was 28.How is her mother now?​
Delvig [45]

Answer:

32

Step-by-step explanation:

Daisy's mom is 4 times as old as she.

m = 4d

The sum of their ages 6 years ago was 28.

(m - 6) + (d - 6) = 28

Substitute for m = 4d

(4d - 6) + (d - 6) = 28

Combine like terms

5d - 12 = 28

5d = 40

Divide by 5

d = 8

m = 4d

m = 4 * 8

m = 32

7 0
3 years ago
What is the solution of 3x + 5 = 2x – 7?
Schach [20]

Answer:

the x-coordinates of the intersection point of the lines y = 3x + 5 and y = 2x – 7

Step-by-step explanation:

When you set two equations or functions equal to each other that is saying you want to know when the graphs intersect.  So the y and x intercept don't matter, unless you combined the terms like this.

3x + 5 = 2x – 7

x + 12 = 0 then that terms x intercept woudl be the x coordinate of the intersection of the other two terms.  But remember, this is onlyif you combines the two functions.  

Of your options you just want the ones dealing with the intersection point.  And of those two we are plugging in x, so we want the x coordinate.

5 0
4 years ago
Please answer question now
IceJOKER [234]
The answer is 41.7 km^2
7 0
3 years ago
Please helppppp meeeeeee!!!!!!!!!!!!!!!!!!!!
astraxan [27]

Answer:option A is the correct answer.

Step-by-step explanation:

The given triangle UVW is a right angle triangle. This is because one of its angles is 90 degrees. The sum of the two other angles is 180. To determine Cos U, we will apply trigonometric ratio.

Cos U = adjacent side/ hypotenuse.

Looking at the triangle with C as the reference angle,

Adjacent side = 12

Hypotenuse( always the longest side of the triangle) = 13

Therefore,

Cos U = 12/13

6 0
3 years ago
9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
4 years ago
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