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Anna [14]
3 years ago
11

Andrew pays $1824 per year in tuition. How much should he budget monthly for it ?

Mathematics
2 answers:
Lina20 [59]3 years ago
4 0
I would so go with B I'm not sure if that's the correct answer though but that's what I would go with
atroni [7]3 years ago
4 0
$1824 divided by the months in a year (12)
D. $152
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Could someone please answer my few questions? That'd be great! I'll give 20 points!!!
Alex Ar [27]
Y=3.6x is direct variation. The constant is 3.6
8y=2x is the same as y=0.25x. It is direct variation, and the constant is 0.25

1. Assuming "dinners made" is on the y-axis, DV is y=2x. The constant is 2

2. This is not direct variation, and therefore does not have a constant of variation
4 0
3 years ago
24÷2²(-3)-7-2²-2(3-6) step by step please and thank you!​
gavmur [86]

Answer:

- 23

Step-by-step explanation:

24 \div {2}^{2} ( - 3) - 7 -  {2}^{2}  - 2(3 - 6) \\ 24 \div  {2}^{2} ( - 3) - 7 -  {2}^{2}  - 2( - 3) \\ 24 \div 4( - 3) - 7 -  4  - 2( - 3)\\ 6(-3) - 7 - 4 -2(- 3) \\  - 18 - 7 - 4 + 6 \\ -25 -4 +6 \\ -29 +6 \\ - 23

8 0
3 years ago
Read 2 more answers
50 students went to Verona. 23 were boys. What percentage were giris?
FrozenT [24]

Answer:

54 percent

Step-by-step explanation:

23 over 50 is .54

5 0
3 years ago
Read 2 more answers
This is the question i need help with
vekshin1
I'm pretty sure it should be the 45. or A
4 0
3 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
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