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3 years ago

Andrew pays $1824 per year in tuition. How much should he budget monthly for it ?

Mathematics

2 answers:

Lina20 [59]3 years ago

4 0

I would so go with B I'm not sure if that's the correct answer though but that's what I would go with

atroni [7]3 years ago

4 0

$1824 divided by the months in a year (12)
D. $152

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PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

vodomira [7]

Finding the discriminate of a quadratic formula determines the number and type of answers.

The formula is b^2 -4(ac)

a = 6. b = -7 and c = -4

-7^2 -4(6*-4) = 145

The answer is a positive number so this means there are 2 real solutions.

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3 years ago

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Find x.______________a0

velikii [3]

Answer:

$x=4$

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

$\frac{2}{y}=\frac{y}{6}$

$y^2=12$

$y=\sqrt{12}$

$y=2\sqrt{3}$

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

$a^2+b^2=c^2$

$2^2+(2\sqrt{3})^2=c^2$

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$c=4$

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

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3 years ago

3. PENTAGON The Pentagon is a five-sided

Sergeu [11.5K]

The answer is 4605 feet since 921 • 5 is 4605. There are 5 sides and each side 921 so 921 • 5 = 4605 would be the answer

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3 years ago

in a recent year the population of califorina was about 2.52x10^7 people its land area is about 4.05x10^5 km^2 what was the aver

Oduvanchick [21]

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3 years ago

Eddi Din [679]

Answer: The relative frequency of column A in group 1= $0.75$

The relative frequency of column B in group 1= $0.25$

The relative frequency of column A in group 2= $0.56$

The relative frequency of column B in group 2= $0.44$

Step-by-step explanation:

The relative frequency is the ration of each frequency by the total value in particular group.

For group 1 : Total =102+34=136

The relative frequency of column A in group 1= $\frac{102}{136}=0.75$

The relative frequency of column B in group 1= $\frac{34}{136}=0.25$

For group 2 : Total =18+14=32

The relative frequency of column A in group 2= $\frac{18}{32}=0.5625\approx0.56$

The relative frequency of column B in group 2= $\frac{18}{32}=0.4375\approx0.44$

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3 years ago