PLEASE HELP !!
2 answers:
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I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.
Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:
a = 1
b = 2
c = 3
d = 4
Simplify into standard form:
Use the quadratic formula to solve:
For functions in the form of
. So in this case:
a = 1
b = -4
c = 2
Plug them in:
Solve for 'x':
So the answer would be A.
Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:
a = 1
b = 2
c = 3
d = 4
Simplify into standard form:
Use the quadratic formula to solve:
For functions in the form of
a = 1
b = -4
c = 2
Plug them in:
Solve for 'x':
So the answer would be A.
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.
Let us find z-score of data point 22.03.
Using probability formula , we will get:
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.