What is the value of 8 in the number 0.837

Mathematics

2 answers:

liraira [26]3 years ago

4 0

the answer is the ones because you start from left then you go to the right and you don't count the 0.

tensa zangetsu [6.8K]3 years ago

3 0

Hello

The value of 8 in the number would be .8 which is 8/10 due to the fact that it is behind the decimal point. It is not large enough to be a whole number, but it is the largest decimal.

You might be interested in

Brady has collected the following data. 11, 15, 15, h, 11. If the range of Brady's data is 9, what is the value of h?

tankabanditka [31]

To find the value of h, you will order the data and then determine if there is enough information to find the missing value knowing that from the beginning of the data to the end is a range of 9.

11, 11, 15, 15, ____ (20)

or

(6)_____, 11, 11, 15, 15

The missing value of h could be 9 or 20.

8 0

3 years ago

5 miles=8km how many miles in 80km

Irina-Kira [14]

5miles/8km = xmiles/80km

8x=400

x=50

4 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .