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aleksandrvk [35]
3 years ago
8

PLEASE HELP URGENT!!! Answer only 28.

Mathematics
1 answer:
disa [49]3 years ago
4 0

Answer:

-2h -16k

Step-by-step explanation:

-2(h+8k)

Distribute

-2h -2 *8k

-2h   -16k

They failed to distribute the minus sign as well as the 2            

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Plz help me I've been dealing with this for 4 days. ​
Sloan [31]

Step-by-step explanation:

(qvp)5=4-5=54643434346

3 0
3 years ago
The product of two whole numbers is 75. Their average is 10. What are the numbers?
Archy [21]

Answer:

15 and 5

Step-by-step explanation:

15 x 5 = 75.

15 + 5 = 20, 20 / 2 = 10. Hope this helps :)

8 0
2 years ago
Read 2 more answers
Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

3 0
2 years ago
Simplify (5b)(-3a). -35ab -15ab 2ab
Fofino [41]
(5b)(-3a)
= (5*(-3))(b*a) (combine like terms)
= -15ab

The final answer is -15ab~
3 0
3 years ago
Read 2 more answers
Evaluate each expression for g = -7 and h = 3 and match it to its value. 1. g + h 2 2. g - h 46 3. h - g -21 4. gh -4 5. g + h2
Ivanshal [37]

Answer:

1. -4

2. -10

3. 13

4. -21

5. 2

6. 46

Step-by-step explanation:

To evaluate the expression, substitute g= -7 and h = 3. Then simplify using order of operations.

1.  g-h = -7 + 3 = -4

2. g-h = -7 - 3 = -10

3. h-g = 3 - -7 = 3+10 = 13

4.gh = -7(3) = -21

5. g+h^2 = -7 + 3^2 = -7+9 = 2

6. g^2-h = (-7)^2 -3 = 49 -3 = 46

3 0
2 years ago
Read 2 more answers
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