Answer:
(14a+3, 21+4) = 1
Step-by-step explanation:
We are going to use the Euclidean Algorithm to prove that these two integers have a gcd of 1.
gcd (14a + 3, 21a + 4) = gcd (14a+3, 7a + 1) = gcd (1, 7a+1) = 1
Therefore,
(14a + 3, 21a + 4) = 1
4(r)^x=y
4(r)^(1)=2
r=1/2
y=4*(1/2)^x
68 should be the answer... Sorry if I'm wrong
Answer:
Step-by-step explanation:
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Answer: 3421.19
Step-by-step explanation:
look up cylinder formula and r= radius which is just the diameter cut in half
