Answer: 7,8,9
Step-by-step explanation:
Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:
= (a + 1)(a + 2) = 72
a² + 2a + a + 2 = 72
a² + 3a + 2 - 72 = a
a² + 3a - 70 = 0
a² + 10a - 7a - 70 = 0
a(a + 10) - 7(a + 10)
a - 7 = 0
a = 7
Since a = 7
a + 1 = 7+1 = 8
a + 2 = 7+2 = 9
The numbers are 7,8 and 9
Answer:
As you must know, If one root of the polynomial 7-√5, the other will be 7+√5 i.e irrational root occur in pairs.
A polynomial function cannot have single unreal i.e irrational root. It always occur in pairs.
So , consider a polynomial function of any degree, if it has a root 7-√5, then it must have another root as 7+√5.
A polynomial can't have 7-√5 as a single root.
The answer is actually D. The limit on the left side is computing the derivative at x = a. The right side value of 7 tells us that f ' (a) = 7
