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Mandarinka [93]
3 years ago
9

Please I need it asap

Mathematics
1 answer:
Sauron [17]3 years ago
3 0

Answer:

5) √(3² + 5²) = √34

6) √(4² - 3²) = √7

7) the visible answers all say exactly the same thing in different ways and are all correct.

Step-by-step explanation:

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What does this equal? I keep getting different answers every time I try it.​
bija089 [108]

Answer:

19/6 ...or... 3.16 repeating

Step-by-step explanation:

4 5/8 + 2/3 = 19/6

5 0
3 years ago
A side of an equilateral triangle is 2/8 cm long. Draw a picture that shows the triangle
lianna [129]
Here you go. I hope this will help

7 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
Divide 2/7÷1/3 what is the answer I need help please help me
d1i1m1o1n [39]

Answer: 0.85714285714

Step-by-step explanation:

I just googled it so yeah

7 0
3 years ago
Howmany days are their in a year
ra1l [238]
365 days are in a year
4 0
3 years ago
Read 2 more answers
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