Hey there!!
In order to solve this equation, we will have to use the distributive property.
What is distributive property?
We will need to distribute one term to the other terms preset.
Example : 4 ( 3x - 1 )
sing distributive property, we will have to distribute the term outside the parenthesis to the terms inside. In this case, we will have to distribute 4 to 3x and -1
( 4 × 3x ) + ( 4 × -1 )
12x + ( -4 )
= 12x - 4
This is after implementing the distributive property.
Now moving back onto the question
4 ( x + 5 ) = 3 ( x - 2 ) - 2 ( x + 2 )
Let us first solve 4 ( x + 5 )
Distribute 4 to x and 5
( 4 × x ) + ( 4 × 5 )
4x + 20
Now let's solve 3 ( x - 2 )
Distribute 3 to x and -2
( 3 × x ) + ( 3 × - 2 )
3x - 6
Solve for -2 ( x + 2 )
Distribute -2 to x and 2
( -2 × x ) + ( -2 × 2 )
-2x - 4
Now, let's get everything back together
4x + 20 = 3x - 6 - 2x - 4
Combine all the like terms
4x + 20 = x - 10
Adding 10 on both sides
4x + 20 + 10 = x - 10 + 10
4x + 30 = x
Subtracting 4x on both sides
4x - 4x + 30 = x - 4x
30 = -3x
Dividing by -3 on both sides
30 / -3 = -3x / -3
- 10 = x
<h2>x = - 10 </h2><h3>Hope my answer helps!</h3>
Answer:
The equation is p=34a+12, and a=7
Step-by-step explanation:
Perimeter is all of the sides added together
p=12a+6a+8+6a+8+10a-4
Combine like-terms
p=34a+12
Solve for a by making p equal to 250
250=34a+12
Subtract 12 from both sides
238=34a
Divide both sides by 34
7=a
The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo
Andreas93 [3]
Answer:
This is the answer because you need to find mean median mode range, first quertile, third quartile
Whisker plot below
Step-by-step explanation:
Mean (Average) 9
Median 9
Range 6
Mode 10, appeared 3 times
Geometric Mean 8.8206311297046
Largest 12
Smallest 6
Sum 99
Count 11
■ 1st quartile (lower quartile) = 7.5
■ 2st quartile (median) = 9
■ 3st quartile (upper quartile) = 10
Answer:
If a = 5 and b = 3, then that means 2a - 3b + 3a = 16
Step-by-step explanation:
2a - 3b + 3a
(2×5) - (3×3) + (3×5)
10 - 9 + 15 = 16
B) 4Na + O₂ → 2Na₂O
b) H₂ + Cl₂ ---> 2HCi
