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Svetllana [295]
3 years ago
11

374 divided by 14 with remainders

Mathematics
2 answers:
LekaFEV [45]3 years ago
7 0

Answer:

26R12

Step-by-step explanation:

26 R 12

26x14=364

376-364=12

ludmilkaskok [199]3 years ago
4 0

Answer:

10 is the reminder you get from dividing 374 by 14

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The sign of the product would be the postitive sign because all three integers have the same sign.
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The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2. Victor has 42 more tools than Ilya. How many too
irga5000 [103]

Answer:

Victor gives 28 tools to IIya.

Step-by-step explanation:

Consider the provided information

The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2

Let V represents the Victor and I represent llya

Therefore,

\frac{V}{I} = \frac{5}{2}

It is given that Victor has 42 more tools than Ilya.

\frac{V}{I} = \frac{5}{2}=\frac{42+I}{I}

Solve the above equation.

\frac{5}{2}=\frac{42+I}{I}

5I=84+2I

3I=84

I=28

Thus, IIya has 28 tools.

Victor has 42 more tools than Ilya. Therefore 42 + 28 = 70.

Victor has 70 tools.

We want to find the number of tools victor needs to give to IIya so that the ratio of the number of Victor's tools to the number of Ilya’s tools will be 3:4

Let Victor gives x tools to IIya. Thus,

\frac{3}{4}=\frac{70-x}{28+x}

3(28+x)=4(70-x)

84+3x=280-4x

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4 0
4 years ago
19 * 15 hello I need help on 19 * 15 + 5 + 6 + 7 - 8 - 5 ​
ivanzaharov [21]

Answer:

290

Step-by-step explanation:

Using PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

(19*15)+5+6+7-8-5=

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290

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Is the relation shown in the arrow diagram a function? Explain.<br>​
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Answer:

We conclude that:

Yes; Each input has only one output.

Step-by-step explanation:

From the given arrow diagram, we can easily determine the table

x            y

2           24

4           8

6          16

8          32

10         32

From the table, it is clear that each input has only one output, in other words, each possible x  value is leading to exactly one y value.

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Therefore, we conclude that:

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